php float number error

Question

I am trying to assign float value in php to variable I tried following,

$_web_lat=‎18.501059;
$_web_long=73.862686;

echo $_web_lat .'='. $_web_long;

[Parse error: syntax error, unexpected '.501059' (T_DNUMBER)]

OR

$_web_lat=floatval('‎18.501059');
$_web_long=floatval('‎‎73.862686');

echo $_web_lat .'='. $_web_long;

Both shows 0 as output? Anyone guide me on this?

Possible duplicate of [PHP parse/syntax errors; and how to solve them?](https://stackoverflow.com/questions/18050071/php-parse-syntax-errors-and-how-to-solve-them) — JJJ, Mar 19 '18 at 08:05

Karlo Kokkak · Accepted Answer · 2018-09-17T10:58:42.980

11

Your code seems to have a hidden character ?

Try copy and use this:

<?php
$_web_lat=18.501059;
$_web_long=73.862686;

echo $_web_lat .'='. $_web_long;

?>

edited Sep 17 '18 at 10:58

answered Mar 19 '18 at 08:01

Karlo Kokkak

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@urban Can you let me know how can I check with `vi` and what is `vi`? – Ayaz Ali Shah Mar 19 '18 at 08:04
The hidden character is before the 18, I see this in php fiddle. – Adder Mar 19 '18 at 08:04
can you please elaborate on this? in my code there is no space/char but it shows error – SK IRT Mar 19 '18 at 08:06
I'm using programmer's notepad. I copied and pasted your code to it, and saw the hidden character that is not visible in your code. – Karlo Kokkak Mar 19 '18 at 08:07
1

@SKIRT You need to copy past the script from this answer, it will be functional – Ayaz Ali Shah Mar 19 '18 at 08:07
@AyazShahI I am running Linux. `vi` is a terminal editor. I have copy/pasted the code snippet into a file using `nano`. `nano` does not display such characters but opening with `vi` does – urban Mar 19 '18 at 08:07
1

Copy your codes into http://phpfiddle.org/ and its editor will show extra characters for both of your code snippets. What editor are you using? – Adder Mar 19 '18 at 08:08
tried in phpfiddle.org and it shows...how come this char added? ..really surprised..But thanks for your help – SK IRT Mar 19 '18 at 08:12
I'm using programmer's notepad. The OP uses codelobster. – Karlo Kokkak Mar 19 '18 at 08:18
great catch though – Rotimi Mar 19 '18 at 08:23

score 0 · Answer 2 · answered Mar 19 '18 at 07:59

Try to write floating values like

<?php

    $_web_lat=floatval('‎18.501059f');
    $_web_long=floatval('‎‎73.862686f');


$float_value_of_var1 = floatval($_web_lat);
$float_value_of_var2 = floatval($_web_long);

echo $float_value_of_var1; // 18.501059
echo $float_value_of_var2; // ‎‎73.862686

?>

score 0 · Answer 3 · answered Mar 19 '18 at 08:07

the sintax error is caused by automatic string conversion do the string operator . (dot concat) if you want avoid this you could use or cast float value ast string

  $_web_lat=‎18.501059;
  $_web_long=73.862686;

  echo (string) $_web_lat .'='. (string>$_web_long;

php float number error

3 Answers3