How to match two consecutive alphabets like AA, BB not AB, BD with Regular expression in python?

Question

I would like to match string of two consecutive alphabets like AA, BB not AB, BD. Python 3.x is my language. Please consider valid alphabets would be capitalized. The followings are examples for valid and not valid strings: To be honest, ^[A-Z]{2} would not work.

Valid: AA, ZZ, DD, EE,
Not valid: AB, DDD, aA, Aa, Cd, DE

does input string contain multiple words? – RomanPerekhrest Mar 19 '18 at 09:22 — RomanPerekhrest, Mar 19 '18 at 09:22
@Roman, No, the input would be a single word. – Sang-il Ahn Mar 19 '18 at 09:27 — Sang-il Ahn, Mar 19 '18 at 09:27

Zenoo · Accepted Answer · 2018-03-19T09:29:47.013

3

You can use grouping to achieve that.

Here is a RegEx that will match any uppercase alphabetical character twice : ([A-Z])\1

Demo.

edited Mar 19 '18 at 09:29

answered Mar 19 '18 at 09:19

Zenoo

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i think he wants only capital letters – Stavros Avramidis Mar 19 '18 at 09:23
@StavrosAvramidis Yeah, I updated it, thanks. – Zenoo Mar 19 '18 at 09:24

How to match two consecutive alphabets like AA, BB not AB, BD with Regular expression in python?

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