Python Looping over an argument in a function

Question

I am being a noob trying to loop over a function from pyxero:

invoices = xero.invoices.filter(page = 1)

The above call returns a list of dictionaries which becomes blank when there are no more pages left: [] . So the iteration would stop when the count of elements in the current list/page would become 0. I am trying to loop and create one big list that contains the elements from page 1 and 2 etc appended

Thanks!

Try this: https://stackoverflow.com/questions/9152431/iterating-over-list-of-dictionaries — fez, Apr 05 '18 at 07:59
Hi, thanks, I ended up doing a while loop which solved the issue. — DBa, Apr 06 '18 at 09:15

score 0 · Accepted Answer · answered Apr 06 '18 at 09:19

Solution, (page needs to be string):

number = 1
list = []
data = xero.invoices.filter(since = datetime(2018, 1, 1), page = str(number))
while len(data) > 0 
    data = xero.invoices.filter(since = datetime(2018, 1, 1), page = str(number))
    list.append(data)
    number += 1

Python Looping over an argument in a function

1 Answers1