Make an HttpPost with params and Body

Question

I need to replicate a Postman POST in Java. Usually I had to make an HttpPost with only params in URL, so it was easy to build:

ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("username", username));
post.setEntity(new UrlEncodedFormEntity(postParameters, Consts.UTF_8));

But what I have to do if I have a POST like the image below where there are Params in URL and Body TOGETHER?? Now I'm making the HttpPost like this:

HttpClient client = HttpClientBuilder.create().build();
HttpPost post = new HttpPost("someUrls.com/upload");
ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("username", username));
postParameters.add(new BasicNameValuePair("password", password));
postParameters.add(new BasicNameValuePair("owner", owner));
postParameters.add(new BasicNameValuePair("destination", destination));
try{
    post.setEntity(new UrlEncodedFormEntity(postParameters, Consts.UTF_8));
    HttpResponse httpResponse = client.execute(post);
    //Do something
}catch (Exception e){
    //Do something
}

But how I put "filename" and "filedata" params in the Body together with the params in the URL? Actually I'm using org.Apache library, but i could consider also others library.

Thanks to anybody that will help!

Could you please share more of your code i.e. how are you making the requests, what type of object is `post` etc. Also you should consider, if you can, using a library to handle the requests e.g. `okhttp` — Guy Grin, Mar 21 '18 at 08:53
@GuyGrin Ok, I've added an example. Thanks for the attention. — Chiuccolo, Mar 21 '18 at 09:12

score 0 · Answer 1 · answered Mar 21 '18 at 10:01

You can use below code to pass the body parameters as "application/x-www-form-urlencoded" in POST method call

package han.code.development;

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.net.URL;

import javax.net.ssl.HttpsURLConnection;

public class HttpPost
{
    public String getDatafromPost()
    {
        BufferedReader br=null;
        String outputData;
        try
        {
            String urlString="https://www.google.com"; //you can replace that with your URL
            URL url=new URL(urlString);
            HttpsURLConnection connection=(HttpsURLConnection) url.openConnection();
            connection.setRequestMethod("POST");
            connection.addRequestProperty("Content-Type", "application/x-www-form-urlencoded");
            connection.addRequestProperty("Authorization", "Replace with your token"); // if you have any accessToken to authorization, just replace
            connection.setDoOutput(true);
            String data="filename=file1&filedata=asdf1234qwer6789";

            PrintWriter out;
            if((data!=null)) 
            {
                 out = new PrintWriter(connection.getOutputStream());
                 out.println(data);
                 out.close();
            }
            System.out.println(connection.getResponseCode()+" "+connection.getResponseMessage());
            br=new BufferedReader(new InputStreamReader(connection.getInputStream()));
            StringBuilder sb=new StringBuilder();
            String str=br.readLine();
            while(str!=null)
            {
                sb.append(str);
                str=br.readLine();
            }

            outputData=sb.toString();
            return outputData;
       }
       catch(Exception e)
       {
           e.printStackTrace();
       }
       return null;
   }
   public static void main(String[] args)
   {
       HttpPost post=new HttpPost();
       System.out.println(post.getDatafromPost());
   }
}

score 0 · Answer 2 · answered Mar 21 '18 at 12:35

0

I think this question, and this question are about similar issues and both have good answers.

I would recommend using this library as it is well maintained and simple to use if you want.

answered Mar 21 '18 at 12:35

Guy Grin

1,968
2
17
38

score 0 · Accepted Answer · answered May 29 '18 at 12:46

I've resolved making this way:

put on POST URL header params;
adding as MultipartEntity the filename and filedata.

Here the code....

private boolean uploadQueue(String username, String password, String filename, byte[] fileData)
{
    HttpClient client = HttpClientBuilder.create().build();
    String URL = "http://post.here.com:8080/";
    HttpPost post = new HttpPost(URL +"?username="+username+"&password="password);

    try
    {
        MultipartEntityBuilder entityBuilder = MultipartEntityBuilder.create();
        entityBuilder.addBinaryBody("filedata", fileData, ContentType.DEFAULT_BINARY, filename);
        entityBuilder.addTextBody("filename", filename);

        post.setEntity(entityBuilder.build());

        HttpResponse httpResponse = client.execute(post);

        if (httpResponse.getStatusLine().getStatusCode() == HttpStatus.SC_OK)
        {
            logger.info(EntityUtils.toString(httpResponse.getEntity()));

            return true;
        } 
        else
        {
            logger.info(EntityUtils.toString(httpResponse.getEntity()));

            return false;
        }
    }
    catch (Exception e)
    {
        logger.error("Error during Updload Queue phase:"+e.getMessage());
    }

    return false;
}

Make an HttpPost with params and Body

3 Answers3