An exception with == vs is?

Question

From what I understand, the == operator checks if two variables are equal, while the is operator checks if two variables have the same identity/ reference the same object. So why is print(id(a) is id(b)) False ? Don't the two variables reference the same integer?

a = 1000000000
b = 1000000000

print(id(a))           #182798416
print(id(b))           #182798416
print(id(a) is id(b))  #False
print(id(a) == id(b))  #True
print(182798416 is 182798416) #True

score 0 · Accepted Answer · answered Mar 21 '18 at 09:54

0

The id function returns a new integer object, each time, so the integer objects are not the same.

answered Mar 21 '18 at 09:54

Daniel

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yes, but interning of integers can make `is` work with low values from -5 to 256 IIRC. – Jean-François Fabre Mar 21 '18 at 09:58
So the function returns different integer objects. In this case it just so happens that the integers are the same, but the objects are not? – MrSoLoDoLo Mar 21 '18 at 10:12

An exception with == vs is?

1 Answers1