Filter array that only contains emails

Question

I want to filter an array that only contains emails,

I did this

 emails = emails.filter((x)=>(x !== (undefined || null || '')))

that delete the empty value, but can accept a value that is not an email.

https://stackoverflow.com/questions/46155/how-to-validate-an-email-address-in-javascript — Pranav C Balan, Mar 21 '18 at 11:27

score 2 · Accepted Answer · answered Mar 21 '18 at 11:32

You can use the regex from the accepted answer here

let re = /^(([^<>()\[\]\\.,;:\s@"]+(\.[^<>()\[\]\\.,;:\s@"]+)*)|(".+"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
emails = emails.filter(e =>e && e.toLowerCase().match(re));

score 1 · Answer 2 · answered Mar 21 '18 at 11:31

Using the regular expression found here you can complete your filter like so:

var emails = [];

emails = emails.filter(e => typeof e == "string" && validEmail(e));

console.log(emails);

function validEmail(email) {
  var re = /^(([^<>()\[\]\\.,;:\s@"]+(\.[^<>()\[\]\\.,;:\s@"]+)*)|(".+"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
  return re.test(email.toLowerCase());
}

Filter array that only contains emails

2 Answers2