Get variable with PHP from JSON

Question

I have been scratching my head with this one and wonder if anybody would be kind enough to give me a pointer. I am extracting some data as a variable from JSON to PHP, and I can do this no problem when there are nested nodes - IF the node is a text but not if the node is a number. I am using json_decode THIS IS NOT THE SAME AS How do I extract data from JSON with PHP?

This is ok

$get_temp = $jsonobj->main->temp;

This is not working

$get_weather = $jsonobj->main->0->weather;

So my question is how do I target the node when it is a number? Thanks

@Dean yes, it is. read the fine answer, there are whole **sections** dedicated to accessing content inside the decoded json. — Félix Adriyel Gagnon-Grenier, Mar 23 '18 at 12:04

score 4 · Answer 1 · answered Mar 21 '18 at 11:56

4

Probabily you have an array into main node.. so you can get its value with an index like this:

$get_weather = $jsonobj->main[0]->weather;

Where 0 is the index that you want to get

answered Mar 21 '18 at 11:56

Alessandro Minoccheri

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Thank you. Brilliant :-) I shall accept answer in a few minutes when it lets me – Dean Mar 21 '18 at 11:59
Glad to help you @Dean ! – Alessandro Minoccheri Mar 21 '18 at 11:59

score 3 · Answer 2 · edited Mar 21 '18 at 12:02

3

$get_weather = $jsonobj->main[$x]->weather;

$x would be the index

edited Mar 21 '18 at 12:02

godot

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answered Mar 21 '18 at 11:58

Jarri

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Darshan Jain · Accepted Answer · 2018-03-21T11:59:13.263

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This should work:

$get_weather = $jsonobj->main[0]->weather;

edited Mar 21 '18 at 11:59

answered Mar 21 '18 at 11:58

Darshan Jain

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@MagnusEriksson - Modified My Answer. – Darshan Jain Mar 21 '18 at 12:02

Get variable with PHP from JSON

3 Answers3