Get the highest values in a hashmap in java

Question

I have a HashMap which contains the following values:

Map<String, Integer> map = new HashMap<>();
map.put("name1", 3);
map.put("name2", 14);
map.put("name3", 4);
map.put("name4", 14);
map.put("name5", 2);
map.put("name6", 6);

How do I get all keys with the highest value? So that I get the following keys in this example:

name2
name4

@alexdzot Sorting has nothing to do with searching for the highest values. — Nikolas Charalambidis, Mar 24 '18 at 22:13
@Aominè Then [this](https://stackoverflow.com/questions/7498751/get-the-keys-with-the-biggest-values-from-a-hashmap) might be a better one. I can only flag once though. — Ivar, Mar 24 '18 at 22:18

Nikolas Charalambidis · Accepted Answer · 2019-09-19T08:40:49.067

The first step is to find the highest value at all.

int max = Collections.max(map.values());

Now iterate through all the entries of the map and add to the list keys associated with the highest value.

List<String> keys = new ArrayList<>();
for (Entry<String, Integer> entry : map.entrySet()) {
    if (entry.getValue()==max) {
        keys.add(entry.getKey());
    }
}

If you like the Java 8 Stream API, try the following:

map.entrySet().stream()
    .filter(entry -> entry.getValue() == max)
    .map(entry -> entry.getKey())
    .collect(Collectors.toList());

Víctor Gil · Answer 2 · 2022-07-15T12:44:16.140

The response from Nikolas Charalambidis is quite neat, but it may be faster to do it in just one step (iteration), supposing that the input map was much larger:

public static List<String> getKeysWithMaxValue(Map<String, Integer> map){
    final List<String> resultList = new ArrayList<String>();
    int currentMaxValue = Integer.MIN_VALUE;
    for (Map.Entry<String, Integer> entry : map.entrySet()){
        if (entry.getValue() > currentMaxValue){
            resultList.clear();
            resultList.add(entry.getKey());
            currentMaxValue = entry.getValue();
        } else if (entry.getValue() == currentMaxValue){
            resultList.add(entry.getKey());
        }            
    }
    return resultList;
}

score 0 · Answer 3 · answered Dec 29 '21 at 20:19

Another way to achieve this by only processing the elements once could be to use an appropriate collector:

Entry<Integer, Set<String>> highestKey = map.entrySet().stream()
    .collect(groupingBy(Entry::getValue, TreeMap::new, mapping(Entry::getKey, toSet())))
    .lastEntry();
Set<String> result = highestKey != null ? highestKey.getValue() : Set.of();

Here we stream() over the entries in the map. By grouping by the value of the entries we can collect into a new map. By stating that it should collect into a TreeMap, it will be sorted according to it's keys. By doing this, we can get the highest value by using lastEntry().

mapping() is used to make sure we get the keys of the original map as the value in the new map, whithout this we would get the entries as values.

Finally, the last null check is needed in case of an empty map, because there won't be any last entry.

A fully working example including imports:

import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;
import java.util.TreeMap;

import static java.util.stream.Collectors.*;

class Sorting {

  public static void main(String[] args) {
    Map<String, Integer> map = Map.of(
        "name1", 3,
        "name2", 14,
        "name3", 4,
        "name4", 14,
        "name5", 2,
        "name6", 6);

    Entry<Integer, Set<String>> highestKey = map.entrySet().stream()
        .collect(groupingBy(Entry::getValue, TreeMap::new, mapping(Entry::getKey, toSet())))
        .lastEntry();
    Set<String> result = highestKey != null ? highestKey.getValue() : Set.of();
  }

}

Get the highest values in a hashmap in java

3 Answers3