Slicing array into 2 parts

Question

I have an array of N elements.

x = [ 1  , 2, ....... , N]

How can i split it into 8:2 arrays?

The first array should have 80% elements and the second rest.

Well break down the problem: How do you calculate the cutoff between the end of the first ~80% and the start of the last ~20%, and then knowing that cuttoff, how do you slice the array? — Alexander, Mar 24 '18 at 22:11

score 2 · Answer 1 · answered Mar 24 '18 at 22:29

In order to calculate the ratio, you need to first find the length of the list x:

len(x)

To find 80% of the list, multiply the length by 80%:

len(x)*.8

This will return a float. You need to convert it into an int for list slicing:

int(len(x)*.8)

Next you need to slice the list. Here is a good resource on the basics of list slicing. It will look something like this:

x[:int(len(x)*.8)]

See if you can figure out how to make the second list for the remaining 20%.

score 2 · Answer 2 · answered Mar 24 '18 at 22:36

2

first enter any list x=[1,2,3....n] then do this function y=(Len(x) * 4) // 5 then split it to 2 lists a=x[0:y] b=x[-(Len(x)-y):]

answered Mar 24 '18 at 22:36

Shehab El-din

2 Answers2