Have you tried compiling it and comparing the byte code? Here are my results. For:
public class Example {
public static void main(String[] args) {
System.out.println("Hello world!");
}
private static class A {
A(){}
}
}
The above yields the following *.class files:
-rw-r--r-- 1 michaelsafyan staff 238 Feb 10 00:11 Example$A.class
-rw-r--r-- 1 michaelsafyan staff 474 Feb 10 00:11 Example.class
Now, if I move the class files, delete the private
modifier, and recompile, I get:
-rw-r--r-- 1 michaelsafyan staff 238 Feb 10 00:15 Example$A.class
-rw-r--r-- 1 michaelsafyan staff 474 Feb 10 00:15 Example.class
If you look at the VM Spec on class files, you'll see that there is a constant-sized bit field for specifying the access modifiers, so it should not be any surprise that the generated files are the same size.
In short, your access modifiers won't affect the size of the generated byte code (it also should not have any performance impact, either). You should use the access modifier that makes the most sense.
I should also add that there is a slight difference if you change the inner class from being declared static
to not being declared static
, as it implies an additional field referencing the outer class. This will take up slightly more memory than if you declared the inner class static
, but you'd be insane to optimize for this (use static
where it makes sense, and where you need it to be non-static, make it non-static, but don't convolute your design just to save a pointer of memory here or there).