Delete an element of array in function

Question

I'm using some functions to delete vars. My code is like:

<?
$arr['var1'] = 'Hello';
$arr['var2'] = 'world';
function foo(){
    global $arr;
    unset($arr['var2']);
} 
foo();

But in the PHP manual:

To unset() a global variable inside of a function, then use the $GLOBALS array to do so:

unset($GLOBALS['arr']['var2']);

Doesn't unset anything because $GLOBALS['arr']['var2'] doesn't exist. I only want to unset GLOBAL array element inside function.

It exists, because GLOBALS are supervariable and it has everything other var has.

edit:

I tried to do it but after I try to call foo() then i try to print_r($arr) it show both var1 and var2, and if I try print_r($GLOBALS['arr']['var2']) it show undefined index.... Maybe it's be config...

edit2

I mistyped it in my script. So it's working...

Full working code:

<?
$arr['var1'] = 'Hello';
$arr['var2'] = 'world';
function foo(){
    global $arr;
    unset($GLOBALS['arr']['var2']);
} 
foo();

_don't unset anything, because $GLOBALS['arr']['var2'] don't exist._ Sure it exists: `print_r($GLOBALS);` — AbraCadaver, Mar 28 '18 at 18:46
Then you're doing something else wrong https://3v4l.org/4FXkE — AbraCadaver, Mar 28 '18 at 18:53
Your function will work ___only you have to call the function___ — RiggsFolly, Mar 28 '18 at 18:53
Possible duplicate of [PHP: Delete an element from an array](https://stackoverflow.com/questions/369602/php-delete-an-element-from-an-array) — hidden_4003, Mar 28 '18 at 18:57
You can paste the code into any online PHP evaluator and it obviously works https://eval.in/980279 or http://sandbox.onlinephpfunctions.com/code/bf946cd94d9f16e392fe4cb00c1375792a20da7f — AbraCadaver, Mar 28 '18 at 18:57
Something odd here. __Please show us the full code and ALL the error messages__ — RiggsFolly, Mar 28 '18 at 18:58
It wasn't inside php code, but in conf... I don't have any **OTHER** errors/warnings.. — Dan B., Mar 28 '18 at 19:14
@DanB.Can you clear my confusion about **I tried to do it but after I try to call foo() then i try to print_r($arr) it show both var1 and var2**, Because on my answer I didn't find this thing :) Have you tried the way I tried? — A l w a y s S u n n y, Mar 29 '18 at 01:41

score 1 · Accepted Answer · answered Mar 28 '18 at 18:50

1

You can pass variable by reference:

$arr['var1'] = 'Hello';
$arr['var2'] = 'world';
function foo(&$a){
    unset($a['var2']);
}
foo($arr);

https://secure.php.net/manual/en/language.references.pass.php

answered Mar 28 '18 at 18:50

Boshentz

347
2
8

score 0 · Answer 2 · answered Mar 28 '18 at 18:48

0

unset($GLOBALS['arr']['var2']); is correct.

see here https://3v4l.org/rCN5h

<?php
$arr['var1'] = 'Hello';
$arr['var2'] = 'world';
function foo(){
unset($GLOBALS['arr']['var2']);
}
var_dump($arr);
foo();
var_dump($arr);

answered Mar 28 '18 at 18:48

hanshenrik

19,904
4
43
89

@DanB. it does work, check again. or just check my link. – hanshenrik Mar 28 '18 at 18:53

Delete an element of array in function

2 Answers2