String Input Validation in Python

Asked Mar 29 '18 at 01:56

Active Mar 29 '18 at 02:05

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I have having trouble coming up with a input validation for my string. I am having the user input 2 numbers. The user would input something like "2(space)3". My validation would include having anything other than a number being inputted go back and re-enter their input. Not asking anyone to write the code, just let me know the easiest way to go about this, I have tried multiple different loops and if statements and not getting anywhere.

print ("\nEquation format: remainder dividor, for example 2 3 means x % 3 = 2\n")
for i in range(0, k):
    print ("Please input equation " + str(i+1))
    s = input()
    a_i, n_i = map(int, s.split())
    a.append(a_i)
    n.append(n_i)

edited Mar 29 '18 at 02:05

Omar Einea

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asked Mar 29 '18 at 01:56

Jacob Gellhaus

I feel like a `while` loop is good for what you need. – Zhiya Mar 29 '18 at 01:57
while not user_input.isdigit(): user_input = input("Please input equation ") should work fine for you, define user_input at the top of your code – Chris Mar 29 '18 at 02:00
What would i set user_input = to? user_input=()?? – Jacob Gellhaus Mar 29 '18 at 02:10
just a blank string will do "" – Chris Mar 29 '18 at 02:12
the problem i am getting is that it is saying that when i enter 4(space)7 it says it is not an integer. There has to be something i can add that detects my space. – Jacob Gellhaus Mar 29 '18 at 02:19
while True: try: userInput = int(input("Please input equation:")) except ValueError: print("not an integer!") This is what i have so far. I have initialized userInput=0 – Jacob Gellhaus Mar 29 '18 at 02:21

String Input Validation in Python

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