How to print Exact data from URL

Question

Using Python how can I print request_token from a URL like:

https://kite.trade/?request_token=p87tOTSXRSp4O20TGr870n2JiXFKISIh&action=login&status=success

IE: the text between = to & following request_token.

Answer 1

I think what you're looking for is parse_qs from urllib.parse.

from urllib.parse import urlparse, parse_qs #import stuff

#parse the url
url_obj = urlparse('https://kite.trade/?request_token=p87tOTSXRSp4O20TGr870n2JiXFKISIh&action=login&status=success')
#get a dictionary from the query
q_dict = parse_qs(url_obj.query)
#now get query args by key name. 
print(q_dict["request_token"])
print(q_dict["status"])

Here is a link to the documentation for parse_qs.

Answer 2

Use the urlparse library in python 2 https://docs.python.org/2/library/urlparse.html

Or urllib.parse in python 3 https://docs.python.org/3/library/urllib.parse.html

Answer 3

You can use split the strings using string functions and put the query into a dict like:

Code:

url = 'https://kite.trade/?request_token=p87tOTSXRSp4O20TGr870n2JiXFKISIh&' \
      'action=login&status=success'

query = dict(a.split('=') for a in url.split('?')[1].split('&'))
print(query)

You can do the same using the urllib like:

import urllib
query = urllib.parse.parse_qs(urllib.parse.urlparse(url).query)
print(query['request_token'][0])

Results:

{'request_token': 'p87tOTSXRSp4O20TGr870n2JiXFKISIh', 'action': 'login', 'status': 'success'}
p87tOTSXRSp4O20TGr870n2JiXFKISIh