How can I parse this data to specified format?

Question

I am trying to parse data from 2018-03-31 15:58 to 2018-03-31T15:58:00Z. Is it possible to achieve this using dataframe or another library?

Possible duplicate of [Parse date string and change format](https://stackoverflow.com/questions/2265357/parse-date-string-and-change-format) — Georgy, Mar 31 '18 at 19:21

score 2 · Accepted Answer · answered Mar 31 '18 at 19:01

2

Using datetime module

import datetime
s = "2018-03-31 15:58"
print(datetime.datetime.strptime(s , "%Y-%m-%d %H:%M").strftime("%Y-%m-%dT%H:%M:%SZ"))

Output:

2018-03-31T15:58:00Z

Or using pandas

import pandas as pd
s = "2018-03-31 15:58"
print(pd.to_datetime(s).strftime("%Y-%m-%dT%H:%M:%SZ"))

answered Mar 31 '18 at 19:01

Rakesh

1 Answers1