Why does this code print 16 in java

Question

Can someone explain the underlying mechanics behind this chunk of code.

System.out.println(0x10);

@AhmedAbdulkareem **0x** represents Hex, **0b** represents Binary and **0** before a number represents Octal - therefore, what you have here is hexadecimal 10 which is 16 in decimal and Java outputs the answer in decimal format :-) — Zippy, Mar 31 '18 at 22:55
See also: [What does "0xFF00" mean?](https://stackoverflow.com/q/24211736) — Bernhard Barker, Mar 31 '18 at 23:34

Svichkarev Anatoly · Answer 1 · 2018-03-31T22:51:27.440

0

0x or 0X in front of the numbers are hex format.

Why 16:

0x1          0

  1 * 16^1 + 0 * 16^0
= 1 * 16   + 0 * 1 
= 16       + 0 
= 16

edited Mar 31 '18 at 22:51

answered Mar 31 '18 at 22:46

score 0 · Answer 2 · answered Mar 31 '18 at 22:47

0

This is a hex number and in decimal it is 16

answered Mar 31 '18 at 22:47

Jurgiele

score 0 · Accepted Answer · answered Mar 31 '18 at 22:51

0

The 0x indicates the compiler that the following literals are supposed to be a hex number witch in your example is 10 hex or 16 decimal

answered Mar 31 '18 at 22:51

tung

3 Answers3