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I want convert integer to byte. If integer bigger than byte range{0,255} then counting from the start. I mean if integer = 260 then function return 5 or if int = 1120 then return 96 and so on.

  • Just cast it to byte: `byte b = (byte) yourInt;` – Evk Apr 02 '18 at 06:51
  • There is a discrepancy in the expected results for this question, so the question marked as a duplicate doesn't answer it sufficiently. The answer below addresses this discrepancy, so I have reopened this question. – Matthew Watson Apr 02 '18 at 08:02

1 Answers1

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You can use:

byte myByte = (byte)(myInt & 0xFF);

However, note that 260 will give 4 instead of five. (E.g. 255->valid, 256->0, 257->1, 258->2, 259->3, 260->4)

If you really want 260 to give 5, then you are probably looking for the remainder after dividing by 255. That can be calculated using:

byte myByte = (byte)(myInt % 255);
Peter Aylett
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  • Is `byte myByte = (byte)(myInt & 0xFF);` any different from directly casting to `byte`? – InBetween Apr 02 '18 at 06:58
  • If primitive operations are enforced to be unchecked, then there is no difference. However, if an overflow check occurs, values outside the range of byte will cause an exception. – dumetrulo Apr 02 '18 at 07:01
  • Note that you could also use `byte myByte = unchecked((byte)myInt);` – Matthew Watson Apr 02 '18 at 07:59
  • Also note that `1120 % 255` is `100` whereas `1120 & 0xff` is `96`. There is a discrepancy in the OP's expected results which s/he will need to address - but this answer correctly states both possible solutions. – Matthew Watson Apr 02 '18 at 08:05