I am creating a GIF from remote files in node currently by downloading each image to the file system into a tmp folder.
I want to bypass saving the image to a tmp folder and save in memory instead. Is this possible?
As you can see, I have a download function in my AWS class which saves to a tmp folder:
download(key){
return new Promise((resolve, reject) => {
request.head(`${this.base_url}/${this.bucket}/${key}`, (err, res, body) => {
request(`${this.base_url}/${this.bucket}/${key}`)
.pipe(fs.createWriteStream(`tmp/${key}`)).on('close', resolve )
})
})
};
Once they have all downloaded, I have a createGif function in my GifService class which adds each file path as a custom argument of gm
, adds a delay of 50ms, resizes then outputs as buffer which I am then uploading to AWS s3.
import gm from 'gm';
...
constructor(){
this.gm = gm()
}
generateGif(images, prefix){
return new Promise((resolve, reject) => {
// for each image we want in array, we pass to gm
images.forEach(image => {
this.gm.in(`tmp/${image.Key}`)
})
// Now we create the gif with 50sec delay between images, sized to 600px x 2
this.gm
.delay(50)
.resize(600,600)
.toBuffer('gif', async (err, buffer) => {
if (err) reject(err)
const params = {
ACL: 'public-read',
Bucket: config.aws_bucket,
ContentType: 'image/gif',
Key: `${prefix}/${uuid()}.gif`,
Body: buffer
}
try{
// uplaod to S3
const upload = await this.aws.upload(params)
// resolve s3 URL
resolve(upload)
}catch(err) {
console.log('err', err)
reject(err)
}
});
})
}
Ideally if I could pass a remote file stream as custom argument, or pass a buffer in as a custom argument as opposed to how I am currently passing in the tmp file path:
images.forEach(image => {
this.gm.in(`tmp/${image.Key}`)
})