Create a dataframe with NLTK synonyms

Question

Good Morning,

I am using NLTK to get synonyms out of a frame of words.

print(df)

col_1   col_2
Book      5
Pen       5 
Pencil    6

def get_synonyms(df, column_name):

df_1 = df["col_1"]

for i in df_1:
    syn = wn.synsets(i)

    for synset in list(wn.all_synsets('n'))[:2]:
        print(i, "-->", synset)
        print("-----------")

        for lemma in synset.lemmas():
            print(lemma.name())
            ci = lemma.name()

return(syn)

And it does work, but I would like to get the following dataframe, with the first "n" synonyms, of each word in "col_1":

print(df_final)

    col_1     synonym
    Book      booklet
    Book      album
    Pen       cage   
    ...

I tried initializing an empty list, before both synset and lemma loop, and appending, but in both cases it didn't work; for example:

synonyms = []
            for lemma in synset.lemmas():
                print(lemma.name())
                ci = lemma.name()
                synonyms.append(ci)

score 2 · Accepted Answer · answered Apr 04 '18 at 09:23

You can use:

from nltk.corpus import wordnet
from itertools import chain

def get_synonyms(df, column_name, N):
    L = []
    for i in df[column_name]:
        syn = wordnet.synsets(i)
        #flatten all lists by chain, remove duplicates by set
        lemmas = list(set(chain.from_iterable([w.lemma_names() for w in syn])))
        for j in lemmas[:N]:
            #append to final list
            L.append([i, j])
    #create DataFrame
    return (pd.DataFrame(L, columns=['word','syn']))    

#add number of filtered synonyms
df1 = get_synonyms(df, 'col_1', 3)
print (df1)
     word           syn
0    Book   record_book
1    Book          book
2    Book          Word
3     Pen  penitentiary
4     Pen       compose
5     Pen           pen
6  Pencil        pencil

Create a dataframe with NLTK synonyms

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