PHP if statement error on echo

Question

I have this code:

    $data = User::all(); //get all users
    $providercounter = $data->pluck('provider'); //just pay attention to their provider column

    if($providercounter == ""){
      echo 'site'.$providercounter->count();
    }ifelse($providercounter == "facebook"){
      echo 'facebook'.$providercounter->count();
}
dd($providercounter);

I'm getting this error:

Parse error: syntax error, unexpected 'echo' (T_ECHO)

on this line:

echo 'facebook'.$providercounter->count();

What I try to do:

I want to get my provider column data, so I can use it in my chart. With code above i try to make something like:

provider = Null -> echo site 20 //20 is count of users which their provider column is null
provider = facebook -> echo facebook 10 //10 is count of users which their provider column is facebook

So I can get count of users of each provider. (facebook 10 users), (site 20 users) etc.

Where I'm wrong?

UPDATE

Thanks for helps now I have results, but not as expected:

Here is my completed code

$data = User::all();
    $providercounter = $data->pluck('provider');
     if($providercounter == ""){
      echo 'site'.$providercounter->count();
    }elseif($providercounter == "facebook"){
      echo 'facebook'.$providercounter->count();
    }elseif($providercounter == "google"){
      echo 'google'.$providercounter->count();
    }elseif($providercounter == "linkedin"){
      echo 'linkedin'.$providercounter->count();
    }elseif($providercounter == "github"){
      echo 'github'.$providercounter->count();
    }
    dd($providercounter);

My result is:

Collection {#634 ▼
  #items: array:4 [▼
    0 => null
    1 => "google"
    2 => "facebook"
    3 => "facebook"
  ]
}

What I expected was something like:

site => 1
facebook => 2

so it has my echo such as site, facebook, etc. and count of their values like 1, 2, ....

Any idea?

Check if/else-conditions http://php.net/manual/de/control-structures.elseif.php — Bernhard, Apr 05 '18 at 06:10

score 4 · Accepted Answer · edited Apr 05 '18 at 06:27

4

Please try the below code

Your issue is with ifelse, it must be elseif

$data = User::all(); //get all users
$providercounter = $data->pluck('provider');

if ($providercounter == "") {
      echo 'site'.$providercounter->count();
} elseif ($providercounter == "facebook") {
      echo 'facebook'.$providercounter->count();
}
dd($providercounter);

edited Apr 05 '18 at 06:27

Qirel

25,449
7
45
62

answered Apr 05 '18 at 06:09

sunny bhadania

423
3
5

thank you i updated my question – mafortis Apr 05 '18 at 06:15

score 1 · Answer 2 · answered Apr 05 '18 at 06:08

1

try with else if

 if($providercounter == ""){
      echo 'site'.$providercounter->count();
    }elseif($providercounter == "facebook"){
      echo 'facebook'.$providercounter->count();
}

answered Apr 05 '18 at 06:08

Rp9

1,955
2
23
31

thank you i updated my question – mafortis Apr 05 '18 at 06:15

score 1 · Answer 3 · answered Apr 05 '18 at 06:15

1

The error you are facing is due to not using else or else if.

Try using

$data = User::all(); //get all users
    $providercounter = $data->pluck('provider'); //just pay attention to their    provider column
    if($providercounter == ""){
      echo 'site'.$providercounter->count();
    }else if($providercounter == "facebook"){
      echo 'facebook'.$providercounter->count(); } dd($providercounter);

answered Apr 05 '18 at 06:15

Rishi Kc

95
9

thank you i updated my question – mafortis Apr 05 '18 at 06:16

PHP if statement error on echo

What I try to do:

UPDATE

3 Answers3