Given a 4 digit year, return the number of the day on which January 1st falls. 0 is Sunday, …, 6 is Saturday
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1This is probably too broad for SO. I would start writing some code and come back if you have a specific issue. – user3483203 Apr 11 '18 at 18:41
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2However, you probably want: `datetime.datetime(1967, 1, 1).weekday()` Although Sunday is 6 in that format, and Monday is 0. – user3483203 Apr 11 '18 at 18:44
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https://stackoverflow.com/questions/9847213/how-do-i-get-the-day-of-week-given-a-date-in-python Might be a dupe. – user3483203 Apr 11 '18 at 18:47
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@Tshilidzi what did you try? – Amitkumar Karnik Apr 12 '18 at 06:17
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You can use the datetime library
import datetime
d = datetime.date(year, 1, 1)
weekday = d.isoweekday() % 7
The datetime library starts all weeks on Monday, so you need to do a bit of a conversion to get Sunday to be 0
Brendan Abel
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@chrisz Yes, for `weekday()`, it's Mon-Sun (0-6), `isoweekday()` is still Mon-Sun, but it runs `1-7`, I'm just converting `7` to `0` – Brendan Abel Apr 11 '18 at 18:48