Looking for a way to send the contents of a HTML file that is generated once a day using this script below. Running into road blocks getting it to work. I can sent HTML and see it, just not sure how to print out the contents of the file and send it.
File Format is export_MM-DD-YY.html
Id rather have it display the contents of the HTML in the email not the HTML file.
#!/usr/bin/env python3
import smtplib
import config
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
filename = 'name_of_file'
# Read a file and encode it into base64 format
fo = open(filename, "rb")
filecontent = fo.read()
encodedcontent = base64.b64encode(filecontent) # base64
filename = os.path.basename(filename)
# me == my email address
# you == recipient's email address
me = "From@example.com"
you = "TO@example.com"
subject = 'Test Subject v5'
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = subject
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttps://www.python.org"
html = """\
**INSERT HTML FILE CONTENTS HERE...**
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(config.EMAIL_ADDRESS, config.PASSWORD)
server.sendmail(me,you,msg.as_string())
server.quit()
So I think I got it working but im sure theres more code here than is needed (If anyone sees anything I can clean up?)
#!/usr/bin/env python3
import smtplib
import os
import config
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
raport_file = open('export.html','rb')
alert_msg = MIMEText(raport_file.read(),"html", "utf-8")
# me == my email address
# you == recipient's email address
me = "From@example.com"
you = "TO@example.com"
subject = 'Test Subject v5'
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = subject
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttps://www.python.org"
html = """\
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(config.EMAIL_ADDRESS, config.PASSWORD)
server.sendmail(me,you,alert_msg.as_string())
server.quit()
