Overloaded C++ function float parameters error

Question

I've been programming a pair of overloaded C++ functions, one taking 2 integer parameters, and the other 2 floats.

But the codeblocks compiler says:

error: call of overloaded 'func(double, double)' is ambiguous

Why double if I'm specifying a float?

I'm using the two functions to sum their values and showing the result on cout inside them. Float values given as arguments are 1.14 and 3.33, not big floating numbers...

Someone knows? thx!

#include <iostream>
using namespace std;

void func(int a, int b) {
    cout << a+b;
}

void func(float a, float b) 
    cout << a+b;
}

int main() {
  func(3, 7);
  func(1.14, 3.33);

}

Because C++ specifies that float values get promoted to doubles. — Sam Varshavchik, Apr 14 '18 at 21:30
`double` isn’t `float`. Calling either function with `double` arguments requires a conversion, and both conversions have the same rank, so the call is ambiguous. — Pete Becker, Apr 14 '18 at 21:42

score 4 · Accepted Answer · edited Oct 16 '21 at 20:47

4

The function call func(1.14, 3.33) is ambiguous because 1.14 and 3.33 are doubles and both can be converted to either int or float. Therefore the compiler does not know which function to call.

You can fix this by explicitly specifying the type of the constants func(float(1.14), float(3.33)) or by changing the overload from func(float, float) to func(double, double).

In this case, explicitly telling the compiler which type to use is probably a better idea.

edited Oct 16 '21 at 20:47

StoryTeller - Unslander Monica

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answered Apr 14 '18 at 21:49

Martin Piala

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Since they are literals you can just use `1.14f` and `3.33f` – Kevin Apr 14 '18 at 21:50

Overloaded C++ function float parameters error

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