PHP: return array values via -> (pointer)

Question

I use below code to get outputs database:

$array = array();
while($row = ...){
   $array[] = $row;
}

return $array;

Now, i can get values:

foreach($array as $in){
   echo $in[title];
}

But i want get values by -> :

foreach($array as $in){
   echo $in->title;
}

score 3 · Accepted Answer · answered Apr 16 '18 at 07:27

3

You could store objects during the while() loop.

Using MySQLi, with fetch_object():

while ($row = $result->fetch_object()) {
    // here, $row is an object
    $array[] = $row;
}

Using PDO, with fetch(), and the PDO::FETCH_OBJ constant:

while ($row = $sth->fetch(PDO::FETCH_OBJ)) {
    // here, $row is an object
    $array[] = $row;
}

Then you could access using ->:

foreach($array as $in){
   echo $in->title;
}

answered Apr 16 '18 at 07:27

Syscall

this is much better.+1 – Alive to die - Anant Apr 16 '18 at 07:30
@Syscall, Thank you. Which is better in general? – Te Me Apr 16 '18 at 07:38
@TeMe Between what and what? PDO and MySQLi or arrays and objects? Is mostly as you prefer, IMHO. Maybe it could depends of what you have to do with your data after that. – Syscall Apr 16 '18 at 07:42
@Syscall Between arrays and objects – Te Me Apr 16 '18 at 07:44
@TeMe As I said in my updated comment, it _could_ depends of what you have to do with your data after that. – Syscall Apr 16 '18 at 07:49

score 0 · Answer 2 · edited Feb 03 '19 at 11:01

0

You can try like this

$object = new stdClass();

foreach ($array as $key => $value)
{
    $object->$key = $value;
}

Or refer to this answer

edited Feb 03 '19 at 11:01

marc_s

answered Apr 16 '18 at 07:19

Mad Coder

2 Answers2