How to split a string into a list in Python?

Question

Here I've got a string looks like that '128,120,119,118,119,118,120,116,116,120,128,121' I want to make it to be a list like this [128,120,119,118,119,118,120,116,116,120,128,121]

So I have ever tried a command 'list' in python to make it be a list

However, the result looks like that ['1', '2', '8', ',', '1', '2', '0', ',', '1', '1', '9', ',', '1', '1', '8', ',', '1', '1', '9', ',', '1', '1', '8', ',', '1', '2', '0', ',', '1', '1', '6', ',', '1', '1', '6', ',', '1', '2', '0', ',', '1', '2', '8', ',', '1', '2', '1'].

Although the type of the string data is list, the cutting point is wrong.

ramganesh · Answer 1 · 2018-04-16T07:55:09.890

3

Use Split method

>>> s = '128,120,119,118,119,118,120,116,116,120,128,121'
>>> l = s.split(',') # Split with ','
>>> [int(i) for i in l] # Change str to int type, *Used list comprehensions
[128, 120, 119, 118, 119, 118, 120, 116, 116, 120, 128, 121]
>>>

edited Apr 16 '18 at 07:55

answered Apr 16 '18 at 07:49

ramganesh

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Thanks for your suggestion! – 陳俊良 Apr 16 '18 at 07:51

Yngve Moe · Accepted Answer · 2018-04-16T07:51:08.813

The str.split() function will help here.

nums = '128,120,119,118,119,118,120,116,116,120,128,121'
num_list = nums.split(',')

The argument is how what character you want to split by.

PS. If you want to split by multiple characters, say in a string where the elements are separated by a comma and a space, like so nums = '128, 120, 119, 118, 119, 118, 120, 116, 116, 120, 128, 121', you can use nums.split(', ').

score 1 · Answer 3 · edited Apr 16 '18 at 07:54

1

You can use the split method for that.

my_string = "128,120,119,118,119,118,120,116,116,120,128,121"
my_list = my_string.split(",")

print my_list

Output:

['128','120','119','118','119','118','120','116','116','120','128','121']

edited Apr 16 '18 at 07:54

Sasikumar Murugesan

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answered Apr 16 '18 at 07:50

subhead

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score 1 · Answer 4 · answered Apr 16 '18 at 07:53

1

a = '128,120,119,118,119,118,120,116,116,120,128,121'

b = [int(l) for l in a.split(',')]

answered Apr 16 '18 at 07:53

Avijit Dasgupta

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Sreeram TP · Answer 5 · 2018-04-16T08:00:47.163

You can split on the basis of , to get a list as you need.

But keep in mind that that list be a list of strings i.e the number 128 will string '128'.

To get an integer list, you need to convert this string list to integer list.

You can do this like shown below.

num_string = '128,120,119,118,119,118,120,116,116,120,128,121'

string_list = num_string.split(',')

int_list = [int(x) for x in string_list]

print(int_list)

score 0 · Answer 6 · answered Apr 16 '18 at 07:54

0

Add a simple statement:

d=[int(c) for c in b]

where b=['1','2',....]

answered Apr 16 '18 at 07:54

MB11

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How to split a string into a list in Python?

6 Answers6