How to loop an argument value in bash

Question

I want to loop over the value of an input argument, something like that

for i in {0..$1} do
  echo $i
done

If i call my script: ./my.sh 2

I want

0
1

But i get

{0..2}

How can i do it ?

Note that the accepted answer on the linked duplicate is *not* actually the best way to do it; I'll have to look for a better dup. — chepner, Apr 16 '18 at 12:52

score 1 · Answer 1 · answered Apr 16 '18 at 12:30

1

#!/usr/bin/env bash

last=$(("$1"-1))
for i in $(seq 0 "$last");
    do echo "$i";
done

answered Apr 16 '18 at 12:30

Rod Elias

1 Answers1