Dictionary in Python and key with value

Question

I have to create a program which will print a greeting only to friendly bears. I have created this program but it gives me all the bears, the angry ones too.

bears = {"Grizzly":"angry", "Brown":"friendly", "Polar":"friendly"}
for bear in bears:
  if "[bear]:friendly":
   print("Hello, "+bear+" bear!")
else:
  print("odd")

Also, make sure your indentation is meaningful. I'm guessing you wanted an `if/else` statement, not a `for/else`. — Tim Pietzcker, Apr 16 '18 at 11:56
The indentation is OK because this is the one that one teacher gave us. — Joaquin, Apr 16 '18 at 11:57
@Joaquin, please read up on dictionaries in the [docs](https://docs.python.org/3/tutorial/datastructures.html#dictionaries). — jpp, Apr 16 '18 at 11:58
the term `for bear in bears` means iterate through each item in the list `bears` and assign it temporarily to `bear` and `bears[bear]` gives the value of `bear` — Vj-, Apr 16 '18 at 11:58
Possible duplicate of [Get key by value in dictionary](https://stackoverflow.com/questions/8023306/get-key-by-value-in-dictionary) — William Perron, Apr 16 '18 at 12:05
Your current edit has nothing in common with the original question. What are you doing? If you want to ask a new question, ask a *new* question. I've rolled back your edit. — Tim Pietzcker, Apr 16 '18 at 12:21

Ivan Vinogradov · Answer 1 · 2018-04-16T12:07:36.580

0

I think it is a better idea to iterate over dict's keys' and values by items() method (or iteritems() if you are using python2):

for bear_name, status in bears.items():  # get key and value for bear
    if status == 'friendly':
        print("Hello, " + bear_name + " bear!")

And polar bears are usually not friendly.

edited Apr 16 '18 at 12:07

answered Apr 16 '18 at 11:57

Ivan Vinogradov

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Answers are generally expected to have some explanation to go along with them – William Perron Apr 16 '18 at 11:59

score 0 · Answer 2 · answered Apr 16 '18 at 14:26

You can use this approach :

bears = {"Grizzly":"angry", "Brown":"friendly", "Polar":"friendly"}

for i,j in bears.items():
    if j=="friendly":
        print("Hello, " + i + " bear!")
    else:
        print('odd')

output:

odd
Hello, Polar bear!
Hello, Brown bear!

score 0 · Answer 3 · answered Apr 21 '20 at 11:18

0

You can use the following, which should give you the output you want:

for bear in bears:
if bears[bear] == "friendly":
    print("Hello, " + bear + " bear!")
else:
    print("odd")

answered Apr 21 '20 at 11:18

hubble

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Dictionary in Python and key with value

3 Answers3