I am trying to create a searching module with PHP 7, MySQL and Bootstrap. The only propblem is that if there is more domain for one role, the role is shown twice with the 2 different domain.
This is the popup window Popup window
This is the 3 table: Tables
I was trying to select the multiple datas from the database and add it to an array, but I am new in PHP and MySQL. This is the PHP code:
$output = '';
$sql="SELECT * FROM (SELECT role.role_id AS roleID, role.role_name AS roleNAME, domain.domain_name AS domainNAME
FROM role
LEFT OUTER JOIN role_domain ON role.role_id=role_domain.role_id
LEFT OUTER JOIN domain ON domain.domain_id=role_domain.domain_id
UNION
SELECT role.role_id AS roleID, role.role_name AS roleNAME, domain.domain_name AS domainNAME
FROM role_domain
RIGHT OUTER JOIN domain ON domain.domain_id=role_domain.domain_id
RIGHT OUTER JOIN role ON role.role_id=role_domain.role_id) AS U
WHERE U.roleID='".$_POST["szerep_id"]."'";
$result = mysqli_query($conn,$sql);
// A query that stores the multiple roles
$query="SELECT role.role_name AS roleName, COUNT(role_domain.role_id) as role_count FROM role
LEFT OUTER JOIN role_domain ON role.role_id = role_domain.role_id
GROUP BY role_domain.role_id
HAVING role_count > 1";
$result1= mysqli_query($conn, $query);
// Put the multiple roles to an array
while($row=mysqli_fetch_array($result1))
{
$inspector[]=$row["roleName"];
}
// Create the table
$output .= '
<div class="table-responsive">
<table class="table table-bordered">';
// If the query has an error, it writes the error
if($result===false)
{
die(print_r(mysqli_error($conn), true));
}
// Fill up the Popup Window with the information provided
while($row=mysqli_fetch_array($result))
{
$output .= '
<tr>
<td><label><b>Role name:</b></label></td>
<td>'.$row["roleNAME"].'</td>
</tr>
<tr>
<td><label><b>Domain:</b></label></td>
<td>'.$row["domainNAME"].'</td>
</tr>
';
}
$output .= "</table></div>";
echo $output;
// Frees all resources for the specified statement
$stmt=$conn->prepare($sql);
mysqli_stmt_free_result($stmt);
}
}
else
{
echo "Connection could not be established.<br />";
die(print_r(mysqli_error($conn), true));
}
Thanks for the help!