<p>Closing on <span>{{ $event->endDate->format('d/m/Y') }}</span></p>
Now my current result is Closing on 13/1/2017.
The result I request for is Closing on 12/1/2017.
how to -1 day from it?
Asked
Active
Viewed 66 times
0
-
It looks like a date-time object, but who really knows? – Xorifelse Apr 17 '18 at 03:39
-
Possible duplicate of [Subtract 1 day with PHP](https://stackoverflow.com/questions/7651263/subtract-1-day-with-php) – Gufran Hasan Apr 17 '18 at 03:43
2 Answers
1
<?php
echo date('d-m-Y',strtotime('-1 day', strtotime(date('13-01-2017'))));
Use strtotime, it support this -1day notation.
or datetime oop way
echo (new DateTime('13-01-2017'))->sub(new DateInterval('P1D'))->format('d-m-Y') ;
In your case,
echo (new DateTime($event->endDate->format('d-m-Y')))->sub(new DateInterval('P1D'))->format('d/m/Y') ;
Wils
- 1,178
- 8
- 24
-
In other words: `echo date('d-m-Y',strtotime('-1 day', strtotime(date($event->endDate->format('d/m/Y')))));` But if this is a datetime object... there are far simpler ways.. – Xorifelse Apr 17 '18 at 03:42
-
-
The problem is that the question contains a template language which is unclear. And what I mean with simpler is seconds, 3600 of them. – Xorifelse Apr 17 '18 at 03:59
-
-
-
-
0
Have a look in the strtotime function.
// Initial date
echo $event->endDate->format('d/m/Y'); // 13/1/2017
// Modify the date
$oneDayAgo = date('Y-m-d H:i:s',
strtotime('-1 day', strtotime($event->endDate->format('d/m/Y'))));
echo $oneDayAgo; // 12/1/2017
Claudio Busatto
- 721
- 7
- 17