Can you someone explain to me this code?

Question

int flags = 22 | 225 | 222;

what is this code i don't understand what's happens>>

Possible duplicate of [How Does The Bitwise & (AND) Work In Java?](https://stackoverflow.com/questions/17256644/how-does-the-bitwise-and-work-in-java) — Joe, Apr 17 '18 at 11:42
"what is this code" - bizarre way of setting it to 255, if they are literal values this looks more like deliberate (but poor) obfuscation of some kind. — Andrew, Apr 17 '18 at 11:47
This bit-wise OR-ing looks **suspicious**. Maybe originally it was in **base 8**: `022 | 0225 | 0222` for Unix user/group/others rights or such. — Joop Eggen, Apr 17 '18 at 11:49

score 4 · Accepted Answer · answered Apr 17 '18 at 11:45

22,  in binary 0000000000010110
225, in binary 0000000011100001
222, in binary 0000000011011110

| is binary OR operator:

The binary OR operation has two inputs and one output. It is like the ADD operation which takes two arguments (two inputs) and produces one result (one output).

A B C

0 OR 0 -> 0

0 OR 1 -> 1

1 OR 0 -> 1

1 OR 1 -> 1

0000000000010110 | 0000000011100001| 0000000011011110 = 0000000011111111 (in decimal 255)

score -1 · Answer 2 · answered Apr 17 '18 at 11:43

-1

| is Bitwise Operators so here you added 22 + 225 + 222 in binary way

answered Apr 17 '18 at 11:43

Elarbi Mohamed Aymen

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| this is an bitwise OR operator it does not mean 22 + 225 + 222. – Amit Kumar Apr 17 '18 at 11:46
the OR operator in a binary is not '+' ? ( i think i wrote that it is 22+ 225 +222 in binary way) – Elarbi Mohamed Aymen Apr 17 '18 at 11:50
Can you please tell me what is the sign of OR operator ? – Elarbi Mohamed Aymen Apr 17 '18 at 11:52
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OR operator -> ||, binary OR operator -> | – N.K Apr 17 '18 at 11:53

Can you someone explain to me this code?

2 Answers2