Cannot Open Safari Browser from Webviewcontroller

Question

I am opening links in Webviewcontroller. I have created a button on webview controller to open that link in Safari Browser. Problem I am facing is when I open url before it get load completely in web view controller, it open in Safari browser successfully. But when URL loaded completely in webview controller, it doesn't open Safari Broswer.

My Code is:

let alertController = UIAlertController(title: nil, message: nil, preferredStyle: UIAlertControllerStyle.actionSheet)
    alertController.addAction(UIAlertAction(title: NSLocalizedString("Open in Safari", comment: ""), style: .default, handler: { (UIAlertAction) -> Void in
        self.openInSafari()
    }))

    if  (UIDevice.current.userInterfaceIdiom == .phone){
        alertController.addAction(UIAlertAction(title:  NSLocalizedString("Cancel",comment: ""), style: .cancel, handler:nil))
    }

And Function to open Safari Browser:

func openInSafari(){

    if #available(iOS 10.0, *) {
        UIApplication.shared.open(URL(string: self.currentUrl)!, options: [:],completionHandler: nil)
    } else {
        UIApplication.shared.openURL(URL(string: self.currentUrl)!)
    }

}

Screenshots:

Yes Url is coming. Function is working properly as I check by applying breakpoint. — rohit phogat, Apr 18 '18 at 11:21
Check this link: https://stackoverflow.com/questions/2899699/uiwebview-open-links-in-safari?rq=1 — BadCodeDeveloper, Apr 18 '18 at 11:38

score 0 · Answer 1 · edited Apr 20 '18 at 11:18

0

Please try this once:

guard let url = URL(string: self.currentUrl) else {
    return //be safe
}

if #available(iOS 10.0, *) {
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
} else {
    UIApplication.shared.openURL(url)
}

edited Apr 20 '18 at 11:18

maxwell

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answered Apr 18 '18 at 11:39

Vineesha V

11
1
6

may i know which ios version you are trying – Vineesha V Apr 18 '18 at 12:05

Cannot Open Safari Browser from Webviewcontroller

1 Answers1