Angular get ElementRef of of the routerLinkActive

Question

As in the title I need to get the ElementRef of the routerLinkActive in order to understand where I need to place an "ink Bar" (e.g. Material Design Tab) in the right position.

here I there is my sideNav menu

  <mat-sidenav fxLayout='column' 
   fxLayoutAlign='start center'#sidenav 
   mode="over" [(opened)]="opened" position="end" 
   class="nav-sidenav">

        <!-- Here the Navigation -->
        <div  class="nav-sidenav-container" fxFlex='1 1 100%'>

          <div class="ink-bar"></div> <!-- I NEED TO MOVE THIS -->
          <ul class="nav">

            <li *ngFor="let menuItem of menuItems" 
             routerLinkActive="active" class="{{menuItem.class}}">
              <a [routerLink]="[menuItem.path]">
                <i class="nav-icon-container">
                  <mat-icon>{{menuItem.icon}}</mat-icon>
                </i>
                <p>{{menuItem.title}}</p>
              </a>
            </li>

          </ul>
        </div>
      </mat-sidenav>

the first "li" element is at 180px the offset between the elements is 60px. But i need to know which is the active element at the beginning (e.g. if user paste the URL in the browser), there is a way to get the ElementRef of the activeLink

What are you trying to achieve here ? Why do you need elementRef? — CornelC, Apr 18 '18 at 13:07
I need to "move" the ink-bar at the side of the active "li" element — ALGDB, Apr 18 '18 at 13:17
Do you know any other way to get the information of which route is active? — ALGDB, Apr 18 '18 at 14:47

score 3 · Accepted Answer · answered Apr 18 '18 at 15:31

You can find the ElementRef by using ViewChildren and querying for RouterLinkActive directive, with read: ElementRef option.

We delay the execution of findActiveLink method in a setTimeout, to give the RouterLinkActive time to update the view with appropriate CSS class.

import { Component, ViewChildren, ElementRef, QueryList } from '@angular/core';
import { RouterLinkActive } from '@angular/router';

@Component({
  selector: 'my-app',
  template: `
  <a [routerLinkActive]="activeClass" routerLink="/">Hello</a>
  <a [routerLinkActive]="activeClass" routerLink="/hello">Hello</a>
  <a [routerLinkActive]="activeClass" routerLink="/world">Hello</a>
  <router-outlet></router-outlet>
  `,
  styleUrls: ['./app.component.css']
})
export class AppComponent {
  activeClass = 'active';

  @ViewChildren(RouterLinkActive, { read: ElementRef })
  linkRefs: QueryList<ElementRef>

  constructor() { }

  ngAfterViewInit() {
    setTimeout(() => {
      const activeEl = this.findActiveLink();
      console.log(activeEl);
    }, 0);
  }

  findActiveLink = (): ElementRef | undefined => {
    return this.linkRefs.toArray()
      .find(e => e.nativeElement.classList.contains(this.activeClass))
  }
}

Live demo

Angular get ElementRef of of the routerLinkActive

1 Answers1