I am displaying the values of a multidimensional array. The values are being displayed but i am getting a notice of Undefined offset

Question

if($numrows>0)
{
    $i=0;
    while($i<count($result_page[$i]))         //This is line 68
    {
        echo "<tr>";
        echo "<td>".$result_page[$i]['product_id']."</td>";
        echo "<td>".$result_page[$i]['product_name']."</td>";
        echo "<td>".$result_page[$i]['product_price']."</td>";
        $i++;
    }
}

This is the notice:

Notice: Undefined offset: 10 in /home/jatin/web/www.exam.com/admin/productlist.php on line 68.

I am getting this notice because when the loop will be executed for the last time then $i will be incremented and it goes out of the length of the array.

Each time the number of elements in the 2nd dimension changes thus I have to use count function.

The notice occurs when the condition is checked for the last time, So all my elements are displayed but the notice occurs.

Please give an appropriate solution.

Possible duplicate of [PHP: "Notice: Undefined variable", "Notice: Undefined index", and "Notice: Undefined offset"](https://stackoverflow.com/questions/4261133/php-notice-undefined-variable-notice-undefined-index-and-notice-undef) — DEarTh, Apr 19 '18 at 10:56
This question is not a duplicate. Please read my whole question and answer it. I know why the error occurs but I need the solution. — Yash M. Hanj, Apr 19 '18 at 10:59
can you share which data comes in `$result_page` @YashM.Hanj — Bhargav Chudasama, Apr 19 '18 at 11:00

score 4 · Answer 1 · answered Apr 19 '18 at 11:42

4

well i found one solution myself also which is not a good option but it also works fine...........use the @ operator like given below ---

while($i<count(@$result_page[$i]))

Answers given by B.Desai and thavaamm are better options though.

answered Apr 19 '18 at 11:42

Yash M. Hanj

495
1
3
15

It is not solution it will only suppresses error messages. – B. Desai Apr 19 '18 at 11:48

score 2 · Answer 2 · answered Feb 24 '20 at 05:48

2

You can also use the following function to suppress the warnings.

error_reporting(E_ERROR | E_PARSE);

answered Feb 24 '20 at 05:48

Gamer

21
3

score 1 · Answer 3 · answered Apr 19 '18 at 11:07

You can check whether the array key is set or not then continue loop

if($numrows>0)
{
    $i=0;
    while(isset($result_page[$i]) && $i<count($result_page[$i])         //This is line 68
    {
        echo "<tr>";
        echo "<td>".$result_page[$i]['product_id']."</td>";
        echo "<td>".$result_page[$i]['product_name']."</td>";
        echo "<td>".$result_page[$i]['product_price']."</td>";
    }
}

score 1 · Answer 4 · answered Apr 19 '18 at 11:27

1

Can you try below one.

if($numrows>0)
{
    foreach($result_page as $row)         
    {
        echo "<tr>";
        echo "<td>".$row['product_id']."</td>";
        echo "<td>".$row['product_name']."</td>";
        echo "<td>".$row['product_price']."</td>";
    }
}

answered Apr 19 '18 at 11:27

Thavaprakash Swaminathan

6,226
2
30
31

well i found one solution myself also which is not a good option but it also works fine...........use the @ operator like this `while($i – Yash M. Hanj Apr 19 '18 at 11:38

score 1 · Accepted Answer · answered Feb 24 '20 at 04:33

1

Using the @ operator will suppress the notice. If only that is what you are looking for. Or you can also use this:

while(isset($result_page[$i]) && $i<count($result_page[$i])

answered Feb 24 '20 at 04:33

Just a Coder

26
3

I am displaying the values of a multidimensional array. The values are being displayed but i am getting a notice of Undefined offset

5 Answers5