10

I have a large xml file stored in a variable. I want to write it directly to an ftp using pysftp. I believe I need to use the pysftp.putfo and this needs a file like object. Here is a minimal example:

from io import StringIO
from pysftp import Connection, CnOpts

cnopts = CnOpts()
cnopts.hostkeys = None
with Connection('localhost'
                    ,username= 'admin'
                    ,password = 'test'
                    ,cnopts=cnopts
                    ) as sftp:
        sftp.putfo(StringIO('xml string'))

I get the following error:

TypeError: Expected unicode or bytes, got None

What am I doing wrong? And is there maybe a simpler and better way of achieving my goal of writing a string variable to a file on an ftp?

Stian
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2 Answers2

17

Your first approach was valid, just specify a filename. In-memory files have no default names, and pysftp doesn't know how to name destination file.

from io import StringIO
from pysftp import Connection

with Connection('localhost', ...) as sftp:
    sftp.putfo(StringIO('xml string'), 'test.txt')

It should just work. Also, as a side note - Paramiko (library used by pysftml) put operation is under the hood calling putfo, it's just a thin wrapper. So from the server perspective, it's totally transparent if a file was uploaded directly from FS or from memory.

Valar
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4

I have found one solution, not sure it is the best:

from io import StringIO
from pysftp import Connection, CnOpts

cnopts = CnOpts()
cnopts.hostkeys = None
with Connection('localhost'
                ,username= 'admin'
                ,password = 'test'
                ,cnopts=cnopts
                ) as sftp:

    f = sftp.open('/folder/filename.xml', 'wb')
    f.write('xml string')

Edit: Discovered why there is no good solution for this. Most FTP-servers will demand that you put a file directly, probably to avoid an undending stream. So my final solution was to create the file locally and use pysft put().

Stian
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