python - iscapitalized()

Asked Apr 20 '18 at 12:27

Active Apr 20 '18 at 12:28

Viewed 914 times

Can we define a function iscaptialized() to check if the first letter of the input string is in upper case?

The below code is not so elegant as I would have to repeat the ifelse for all the 26 alphabets. Is there an alternate/elegant way to define?

    def iscapitalized():
        if word.startswith('A'):
           print('True')
       else:
           print('False')

    word = input('Enter a word:')
    iscapitalized()

asked Apr 20 '18 at 12:27

user9674728

1

[isupper()](https://docs.python.org/3/library/stdtypes.html#str.isupper) – 001 Apr 20 '18 at 12:28
3

`word[0].isupper()` – Gert Kommer Apr 20 '18 at 12:28
`isupper()`: "Return true if **all** cased characters in the string are uppercase and there is at least one cased character, false otherwise" – Apr 20 '18 at 12:30
2

@LutzHorn thats why you use the `[0]` – Gert Kommer Apr 20 '18 at 12:31
@GertKommer has the powerful way to do it `def iscapitalized(word): return word[0].isupper()` – Lemayzeur Apr 20 '18 at 12:36
yeah word[0].isupper() is easy! Thank you @Gert – user9674728 Apr 20 '18 at 12:39

python - iscapitalized()

0 Answers0