I want to take string and integer together so that if user enters add y then it perform add and if set x then initialize the value

Question

import java.io.*;
import java.math.*;
import java.text.*;
import java.util.*;
import java.util.regex.*;

public class Solution {

    static long maximumProgramValue(int n) {
        long x=0l,y=0l;
        long count=0l;
        while(n!=0) {
            String s=scanner.nextLine();
            if(s.next().equals("add")) {
                y=s.nextLong();
                x=x+y;
            } else {
                y=s.nextLong();
            }
            if(count < x)
            count=x;
            n--;
        }
        return count ;
    }
    
    private static final Scanner scanner = new Scanner(System.in);
    
    public static void main(String[] args) throws IOException {
        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
        int n = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])*");
        long result = maximumProgramValue(n);
        bufferedWriter.write(String.valueOf(result));
        bufferedWriter.newLine();
        bufferedWriter.close();
        scanner.close();
    }
}

I am getting this error please help

Solution.java:21: error: cannot find symbol
            if(s.next().equals("add"))
                ^
  symbol:   method next()
  location: variable s of type String
Solution.java:23: error: cannot find symbol
                y=s.nextLong();
                   ^
  symbol:   method nextLong()
  location: variable s of type String
Solution.java:28: error: cannot find symbol
              y=s.nextLong();   
                 ^
  symbol:   method nextLong()
  location: variable s of type String
3 errors
Exit Status

Please look at [What does a “Cannot find symbol” compilation error mean?](http://stackoverflow.com/questions/25706216/what-does-a-cannot-find-symbol-compilation-error-mean) — Hovercraft Full Of Eels, Apr 21 '18 at 03:19

Shanu Gupta · Answer 1 · 2018-04-21T03:24:14.983

0

Your

 if(s.next().equals("add"))

should be

 if("add".equals(s))

s is of type String already. There's no use of next() method call on it.

You should convert String to long as follows

y = Long.parseLong(s);

edited Apr 21 '18 at 03:24

answered Apr 21 '18 at 03:19

Shanu Gupta

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it is saying can not find symbol s – rs dwd Apr 21 '18 at 03:20
and what about s.nextLong(); ? – rs dwd Apr 21 '18 at 03:22
You are invking `next` and `nextLong` which `String` doesn't have. – Shanu Gupta Apr 21 '18 at 03:22
so how can I get the value of integer when user enters add 5, i have got add but what about 5 – rs dwd Apr 21 '18 at 03:24
so how can I do this ? – rs dwd Apr 21 '18 at 03:25
Shanu, read [What is a Help Vampire](https://meta.stackoverflow.com/questions/258206/what-is-a-help-vampire). You've got one here -- don't feed it. – Hovercraft Full Of Eels Apr 21 '18 at 03:26
Thanks @HovercraftFullOfEels I don't understand the downvote though. – Shanu Gupta Apr 21 '18 at 03:28

I want to take string and integer together so that if user enters add y then it perform add and if set x then initialize the value

1 Answers1