This is the superclass:Glyph
public class Glyph {
void draw() {
System.out.println("Glyph.draw(");
}
Glyph() {
System.out.println("Glyph() before draw()");
draw();
System.out.println("Glyph() after draw()");
}
}
This is the subclass RoundGlyph
class RoundGlyph extends Glyph {
int radius = 1;
RoundGlyph(int r) {
super();
radius = r;
System.out.println("RoundGlyph.RoundGlyph(), radius = " + radius);
}
void draw() {
System.out.println("RoundGlyph.draw(), radius = " + radius);
}
}
We use this class to test.
public class PolyConstructors {
public static void main(String[] args) {
new RoundGlyph(5);
}
}
Output:
Glyph() before draw()
RoundGlyph.draw(), radius = 0
Glyph() after draw()
RoundGlyph.RoundGlyph(), radius = 5
Why the program execute the method draw()
in class RoundGlyph
when it is executing the super()
?
and print
RoundGlyph.draw(), radius = 0