Regarding $location.$$absUrl multiple condition

Question

Can we check condition like below if not then what is other way??? I need to show console.log only below URl.

$location.$$absUrl.includes('localhost' || 'qa1' || 'cat1')

Below are my URL:

https://localhost:9005/

https://qa1.abc.com/

https://cat1.abc.com/

What are you trying to achieve ? you can current url from `var absUrl = $location.absUrl();` — Shashank Vivek, Apr 23 '18 at 06:39
@ Shashank Vivek need to show console.log on mention URL.... else hide console.log. — Rahul Pawar, Apr 23 '18 at 06:40

score 1 · Answer 1 · answered Apr 23 '18 at 06:43

1

Try:

var absUrl = $location.absUrl();
if(absUrl.match(/(localhost|qa1|cat1)/)){
   console.log(absUrl)
}

answered Apr 23 '18 at 06:43

Shashank Vivek

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Yanis-git · Accepted Answer · 2018-04-23T06:48:38.760

1

to achieve what you expect, you should use regex pattern.

// If my domain contain localhost OR qua1 or cat1.
if (!$location.absUrl().match(/(localhost|qa1|cat1)/)) {
    // then override console.log to empty function.
    console.log = function(){ }; 

    //Is equal to do : window['console']['log'] = function(){ };
}

UPDATE

if you want to disable all kind of console output check this other topic

edited Apr 23 '18 at 06:48

answered Apr 23 '18 at 06:43

Yanis-git

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Thanks for sharing... -:)-:) – Rahul Pawar Apr 23 '18 at 07:17

Regarding $location.$$absUrl multiple condition

2 Answers2