Generate a random string value for each

Asked Apr 23 '18 at 13:11

Active Apr 23 '18 at 13:11

Viewed 51 times

I am fetching "Key" and "Value" from the DB and for each I want to insert a random string in value field.

Problem is that every "Value" field gets the same random string (same random value). How can they get random string, separately, each one different?

foreach (var fields in formFields)
                {
                    FieldValues.Add(new FieldValues
                    {
                        Key = item.Key,
                        Value = RandomString(10,true)
                    });
                }


public string RandomString(int size, bool lowerCase)
        {
            StringBuilder builder = new StringBuilder();
            Random random = new Random();
            char ch;
            for (int i = 0; i < size; i++)
            {
                ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)));
                builder.Append(ch);
            }
            if (lowerCase)
                return builder.ToString().ToLower();
            return builder.ToString();
        }

asked Apr 23 '18 at 13:11

Ovakos

2

https://stackoverflow.com/questions/767999/random-number-generator-only-generating-one-random-number – Corak Apr 23 '18 at 13:12
@Fubo, it is copy/paste from the another page. – Ovakos Apr 23 '18 at 13:13
1

`System.Guid.NewGuid().ToString("N").ToUpper();` will create a nice random string. – Apr 23 '18 at 13:19
in one line `return string.Concat(Enumerable.Range(0, size).Select(x => (char)((lowerCase ? 'a' : 'A') + random.Next(26))));` – fubo Apr 23 '18 at 13:23
Yes but it is still giving same string to all values. – Ovakos Apr 23 '18 at 13:30
as the duplicate mark says, the issue is at `Random random = new Random();` – fubo Apr 23 '18 at 13:50

Generate a random string value for each

0 Answers0