Straddle Checkboard Cipher decryption, list operation

Question

What I want to do is convert a string like:

    "77 65 84"

To a list like:

    ["77", "65", "84"]

I tried the list() function but it does not work.

score 0 · Answer 1 · answered Apr 23 '18 at 17:30

0

answered Apr 23 '18 at 17:30

nosklo

score 0 · Answer 2 · answered Apr 23 '18 at 17:33

0

Use .split()

test_str = "77 65 84"
test_list = test_str.split()

for i in test_list:
  print(i)

So after .split() test_list[0]=77 , test_list[1]=65 etc..

answered Apr 23 '18 at 17:33

NBlaine

score 0 · Answer 3 · answered Apr 23 '18 at 17:36

Use split()

>>> my_string = "77 65 84"
>>> my_list = my_string.split()
>>> my_list
['77', '65', '84']

You can do the same thing by specifying the separator, like so:

>>> comma_string = "74,65,84"
>>> comma_list = comma_string.split(",")
>>> comma_list
['74', '65', '84']

3 Answers3