Start a program that is in Program Files folder

Question

I want to start an exe with java.
This exe is in the Program Files (x86) folder and when I try :

Runtime.getRuntime().exec("C:\\Program Files (x86)\\CodFiscExtractor\\MySQLServer\\MySqlStart.exe");

the console displays me this error :

CreateProcess error=740, The requested operation requires elevation

What I should do?

EDIT : this is not a duplicate of this, because i'm asking java

Possible duplicate of [Redirect standard output and prompt for UAC with ProcessStartInfo](https://stackoverflow.com/questions/18660014/redirect-standard-output-and-prompt-for-uac-with-processstartinfo) — Jeffrey Samarziya, Apr 23 '18 at 19:43
@JeffreySamarziya that is not a duplicate as this is a Java question and that one is WPF. It's certainly related and could be helpful, but not a dupe. — Robert Columbia, Apr 24 '18 at 14:10

score 1 · Accepted Answer · answered Apr 23 '18 at 21:34

I resolved, simply I writed like this :

Runtime.getRuntime().exec("cmd /c \"C:\\Program Files (x86)\\CodFiscExtractor\\MySQLServer\\MySqlStart.exe\"");

Now I don't have error, but I am insterested to don't show UAC window, because MySqlStart.exe starts with admin privileges.

1 Answers1