Regular expression in Swift to validate Cardholder name

Question

I am looking for a regular expression to use in Swift to validate cardholder name for a credit card. I am looking for a regEx which:

I was using this

"^[^-\\s][\\p{L}\\-'\\s]{2,26}$"

but it only accepts dash (-) no apostrophe (')

Highly recommend using regex101.com to test out and refine your regular expression. https://regex101.com/ — Mike Taverne, Apr 24 '18 at 01:51

alsjflalasjf.dev · Accepted Answer · 2018-04-24T02:54:37.947

4

try with this regex

(?<! )[-a-zA-Z' ]{2,26}

see here

https://regex101.com/r/0UVvR1/1

edited Apr 24 '18 at 02:54

answered Apr 24 '18 at 01:51

alsjflalasjf.dev

This regex is not validating John Mc'Kenzie. It's not taking spaces between the first name last name as well. – Somya Apr 24 '18 at 02:43
*I am looking for a regEx which - - Has minimum 2 and maximum 26 characters - Accept dashes (-) and apostrophes (') only and no other special character - Capital and small alphabets and no numbers. - Should not start with a blank space*>>> you didn't ask for that... try now – alsjflalasjf.dev Apr 24 '18 at 02:53
Card holder name may also contain dots (.) like John F. Kennedy or Mrs. Robinson – heximal Dec 12 '18 at 14:21
OP explicitly asks for this `Has minimum 2 and maximum 26 characters - Accept dashes (-) and apostrophes (') only and no other special character`; so, she/he didn't want dots to be a valid char; but, sure, you can add dots too. – alsjflalasjf.dev Dec 12 '18 at 14:38

score 3 · Answer 2 · answered Apr 25 '18 at 06:32

Guessing from your description, this is what you are looking for:

^[\p{L}'-][\p{L}' -]{1,25}$

A few remarks:

you propbably do not want to allow all possible white-space chars [\r\n\t\f\v ] but just spaces.
you have to adjust the allowed lenght of the second string if you add a 1st group that does not include space and dash (since that group contributs an additional character).
with \p{L} you allow any kind of letter from any language (which is good); otherwise use [a-zA-z] if just want to allow the regular (ASCII) alphabet.

PS: Do not forget to escape the pattern properly: "^[\\p{L}'][\\p{L}' -]{1,25}$"

2 Answers2