how execute curl command in python?

Question

I have this command and need to execute my program in python

curl -H 'Content-Type: application/x-ndjson' -XPOST '192.168.1.149:9200/shakespeare/doc/_bulk?pretty' --data-binary @file.json

See https://stackoverflow.com/questions/89228/calling-an-external-command-in-python — Increasingly Idiotic, Apr 24 '18 at 07:56
Possible duplicate of [Calling an external command in Python](https://stackoverflow.com/questions/89228/calling-an-external-command-in-python) — SiHa, Apr 24 '18 at 07:57

score 0 · Answer 1 · answered Apr 24 '18 at 08:04

0

use requests - HTTP for humans, which allows you to send any HTTP query you like

import requests
r = requests.post('192.168.1.149:9200/shakespeare/doc/_bulk?pretty', json=datadict)
print(r.text)

answered Apr 24 '18 at 08:04

umläute

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score 0 · Answer 2 · answered Apr 24 '18 at 09:11

Try something like this:

import requests
import json

headers = {
    'Content-Type': 'application/x-ndjson',
}

params = (('pretty', ''),)

data = open('file.json', 'rb').read()
response = requests.post('http://192.168.1.149:9200/shakespeare/doc/_bulk', headers=headers, params=params, data=data)
print(response.text)

Note: This is just a example according to your curl command.

Thankyou! Hope it helps you! :)

how execute curl command in python?

2 Answers2