IF: how to refer the multiplication of function outputs to the command TEST

Question

So I'm curling a json file and parsing it. The result is a number. Each one of these functions outputs a different number. I want the output in a Math equation, that's gonna go in IF statements.

function func() {
    curl -Ss -H 'Cache-Control: no-cache' url.com | jq -r '.[] | .[] | 
.interger'
}
function func2() {
    curl -Ss -H 'Cache-Control: no-cache' url.com | jq -r '.[] | .[] | 
.interger'
}
function func3() {
    curl -Ss -H 'Cache-Control: no-cache' url.com | jq -r '.[] | .[] | 
.interger'
}


if func*func2*func3 / func2*func3*func -ge 1
then
echo "yay"
fi
if func*func2*func3 / func2*func3*func -lt 1
then
echo "nay"
fi

Currently It is not doing any type of multiplication or division on the if statement, therefore making statement obsolete.

So far I've tried:

if [func*func2*func3 / func2*func3*func -ge 1]
then
echo "yay"
fi
if [func*func2*func3 / func2*func3*func -lt 1]
then
echo "nay"
fi

Not the same this is with functions not variables, so its not a duplicate — Caucasian Malaysian, Apr 28 '18 at 02:37

score 1 · Accepted Answer · answered Apr 25 '18 at 23:36

1

Arithmetic is done with ((...)). Capturing output is done with $(...).

if (($(func)*$(func2)*$(func3) / $(func2)*$(func3)*$(func) >= 1)); then
    echo "yay"
fi

answered Apr 25 '18 at 23:36

John Kugelman

349,597
67
533
578

./blah.sh: line 28: 0.069290 0.069291 0.069266 0.069263 * 0.029013 0.029014 0.029003 0.028957 * 0.419282 0.419409 0.418156 0.417817 : syntax error: invalid arithmetic operator (error token is ".069290 0.069291 0.069266 0.069263 * 0.029013 0.029014 0.029003 0.028957 * 0.419282 0.419409 0.418156 0.417817 ") – Caucasian Malaysian Apr 25 '18 at 23:47
thats the output with your script ^^ – Caucasian Malaysian Apr 25 '18 at 23:47
Bash doesn't do floating point arithmetic. – John Kugelman Apr 25 '18 at 23:48
Floating point arithmentic?, I'm sorry I"m kinda new – Caucasian Malaysian Apr 25 '18 at 23:49

score 0 · Answer 2 · answered Apr 25 '18 at 23:41

0

Try this:

if [[ $(( $(func) * $(func2) * $(func3) )) -gt 1 ]]; then
  echo yay
else
  echo nay
fi

The $(func) calls substitute the value in the command; the $(( ... )) performs arithmetic evaluation.

answered Apr 25 '18 at 23:41

PhilR

5,375
1
21
27

IF: how to refer the multiplication of function outputs to the command TEST

2 Answers2