Having an issue passing a variable from a while mysqli_fetch_array loop to another page so I can use it with $_GET on the other side

Question

Hello I am trying to use $_GET to pass a variable over to the contact.php page mentioned, but the outcome is:

/contact.php?firstname=

this is the link that im clicking to send the variable:

echo '<a href="contact.php?name="' . $email . '">';

This is the code to get the variable on the other side:

 <?php
      $name = $_GET['name'];
      echo $name ;
    ?>

$email is populated by $email = $row['email']; which is in a while mysqli_fetch_array which is getting that data — Ciaran Beatty, Apr 26 '18 at 16:22
I have tested it by echoing $email and it echoes the email address — Ciaran Beatty, Apr 26 '18 at 16:24
while I am here though is there a way to pass two variables over using $_GET or is it only possible with one? — Ciaran Beatty, Apr 26 '18 at 16:26
@CiaranBeatty you can pass as many as you like: `param1=1&param2=2&[...]`. Please read up on `$_GET`. — Script47, Apr 26 '18 at 16:27

score 0 · Accepted Answer · answered Apr 26 '18 at 16:27

0

You are closing the href attributes value before you should be.

echo '<a href="contact.php?name="' . $email . '">';
                                ^

You need to remove that double quote so the value comes out in the attribute. As written currently your HTML will be:

<a href="contact.php?name=" email@example.com">

so use:

echo '<a href="contact.php?name=' . $email . '">';

answered Apr 26 '18 at 16:27

chris85

1

Question should be closed as a typo if you're going to reopen. – Jay Blanchard Apr 26 '18 at 16:28
That's why I left too @chris85 - just popped in today to see what was what. Hell, I don't even run my comment macro any more. Fighting a losing battle. I am soured on the experience. – Jay Blanchard Apr 26 '18 at 16:32
2

Well thank you very much for your help @chris85 it helped me out loads! – Ciaran Beatty Apr 26 '18 at 16:34

1 Answers1