Set application.properties value from JNDI Environment value

Asked Apr 27 '18 at 00:51

Active Apr 27 '18 at 01:52

Viewed 1,037 times

I am building a spring boot application, that has RabbitMQ configuration like below.

spring.rabbitmq.host=host
spring.rabbitmq.port=5672
spring.rabbitmq.username=userName
spring.rabbitmq.password=password

I need to set environment specific configuration. But that configuration needs to be read from tomcat context.xml file. I would need to pass the values for host, username, and password by reading from tomcat Environment tag set in context.xml.

How can I do this?

Spring docs says: 24.3 Application Property Files

If your application runs in a container, then JNDI properties (in java:comp/env) or servlet context initialization parameters can be used instead of, or as well as, environment variables or system properties.

can they be directly used like this:

spring.rabbitmq.host="${rabbitMQHost}"
spring.rabbitmq.port=5672
spring.rabbitmq.username=${rabbitMQUserName}
spring.rabbitmq.password=${rabbitMQPassword}

edited Apr 27 '18 at 01:52

asked Apr 27 '18 at 00:51

Rax

Not with the double quotes as you've used in `spring.rabbitmq.host="${rabbitMQHost}"` – N00b Pr0grammer Apr 27 '18 at 14:08
@N00b Pr0grammer, how can I achieve this? – Rax Apr 27 '18 at 14:10
Check if this helps @Rax -> https://stackoverflow.com/questions/43866691/springboot-read-tomcat-context-xml – N00b Pr0grammer Apr 27 '18 at 14:25

Set application.properties value from JNDI Environment value

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