The result of the addition of a char and an int

Question

Consider the following code:

System.out.println('G'+2);

The output is 73. Can I know why and how?

Because the `int` value of character `G` is `71` ? – Arnaud Apr 27 '18 at 10:16 — Arnaud, Apr 27 '18 at 10:16

xingbin · Accepted Answer · 2018-04-27T10:34:27.927

3

In java, a char occupies 16 bit in UTF-16 encoding.

G's unicode is U+0047, in binary 0000 0000 0100 1111.

When you sum a char and an int(32 bit), the char will be converted to int by inserting 0 into the begin of its binary representation. So 0000 0000 0100 1111 is converted to 0000 0000 0000 0000 0000 0000 0100 1111(in decimal, 71).

That's why you get 73.

edited Apr 27 '18 at 10:34

answered Apr 27 '18 at 10:17

xingbin

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It's unicode representation, not ascii. – Apr 27 '18 at 10:19
`convert` sounds more reasonable. – xingbin Apr 27 '18 at 10:38
@saka1029 That's right. Since 0-128 get the same character in ascii and unicode, I always mix it up. Thanks for pointing it out. – xingbin Apr 27 '18 at 10:41
The fact that ASCII exists is hardly relevant in modern programming environments (except when coding to particular RFCs and perhaps in the tiniest processors.) Basically, if you don't know you are absolutely using ASCII, you almost certainly aren't. – Tom Blodget Apr 27 '18 at 10:47
@TomBlodget I agree with you. – xingbin Apr 27 '18 at 10:49
Good anwser Sir ! – Abdo Bmz Apr 27 '18 at 19:20

score 0 · Answer 2 · answered Apr 27 '18 at 10:19

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It takes ascii value of G and adds 2 to it.

answered Apr 27 '18 at 10:19

Gaurav Kumar

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It's unocode value not ascii. – Apr 27 '18 at 10:23

score 0 · Answer 3 · answered Apr 27 '18 at 10:23

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In code you are going to add character to int. Value of character 'G' is :71

See this for more details: ascii table

answered Apr 27 '18 at 10:23

MinA

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java uses unicode not ascii. – Apr 27 '18 at 10:26

The result of the addition of a char and an int

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