How can I print a number without rounding?(Python)

Question

Edit: I saw the two similar questions but I didn't get my answer.

I want to square some numbers with 4 numbers after the decimal point:

import math
lis=math.sqrt(19)
print("%.4f" % lis)

sqrt(19)=4.35889894 so the output will be:

4.3589

and I want it to be:

4.3588

without rounding up. What do I do?

Because `round` use 2 value (src,dst), if you want escape SRC+2,DEST. — dsgdfg, Apr 27 '18 at 12:40
Strange. This is exactly the same example as here: https://stackoverflow.com/questions/49592945/how-to-prevent-automatic-rounding-in-print-function-when-printing-a-float-number — Georgy, Apr 27 '18 at 12:43
i not type as an answer and not read this article! And you try bad! — dsgdfg, Apr 27 '18 at 12:44

onlyphantom · Accepted Answer · 2018-04-27T12:39:13.890

1

Use math.floor to always round down. Wrap the final output in math.floor and that will do it.

import math
lis=math.sqrt(19)
print(math.floor(lis * 10000)/10000.0)

returns 4.3588

edited Apr 27 '18 at 12:39

answered Apr 27 '18 at 12:31

onlyphantom

I edited the code a bit to gave you that precision of a float. But `math.floor()` do the trick and is easily understandable. – onlyphantom Apr 27 '18 at 12:40
Only if you take this too literally and downvote instantly without thinking... See [here](https://stackoverflow.com/questions/29246455/python-setting-decimal-place-range-without-rounding?utm_medium=organic&utm_source=google_rich_qa&utm_campaign=google_rich_qa) – Alexander Harnisch Apr 27 '18 at 12:45
Yeah no offense taken but @HoseinShendabadi this does exactly what you need and it doesn't feel hackerish at all, so not sure why you downvoted it or didn't want to accept it as an answer? – onlyphantom Apr 27 '18 at 12:49
@onlyphantom I'm sorry pal but the code returned "4" to me – Hosein Shendabadi Apr 27 '18 at 12:51
hmm @HoseinShendabadi Did you see the edited code that I put up 12 mins ago? `print(math.floor(lis * 10000)/10000.0)` returned exactly 4.3588 - which is what you asked for. – onlyphantom Apr 27 '18 at 12:52
@onlyphantom My bad :) . – Hosein Shendabadi Apr 27 '18 at 12:57

score 0 · Answer 2 · answered Apr 27 '18 at 12:36

0

Well, this is more of a hack

float(str(math.sqrt(19))[:6])

Let me know if this isn't something that solves your problem

answered Apr 27 '18 at 12:36

Sushant

why `[:-2]` ? your definition isn't global ! – dsgdfg Apr 27 '18 at 12:38
What do you mean by global? – Sushant Apr 27 '18 at 12:41
`float(str(math.sqrt(1900000))[:6])` ????? – dsgdfg Apr 27 '18 at 12:41
As I said, it's a hack. Also, case specific to the question. That's why I've asked the op to let me know if they need another approach – Sushant Apr 27 '18 at 12:42
It worked with something like 19 But when I input a number like 4 it returns "2.0" but I need "2.0000" – Hosein Shendabadi Apr 27 '18 at 12:46

2 Answers2