Using variables in bash script command parameters

Asked Apr 28 '18 at 15:36

Active Apr 28 '18 at 15:36

Viewed 21 times

I've been trying to start a number of terminals based on a variable i and execute a command in each of them:

#!/bin/bash
read number
for ((i=1;i<=number;i++))
do
xterm -e 'cockroach start --insecure --store="node${i}"'
done

However it doesn't seems to replace ${i} for me in the parameter of the command. I've tried using --store=node${i}, --store=node$i or --store="node" + ${i} none seem to work.

Anything I'm doing wrong?

asked Apr 28 '18 at 15:36

Robin Schmidt

2

See: [Difference between single and double quotes in bash](http://stackoverflow.com/q/6697753/3776858) – Cyrus Apr 28 '18 at 15:38
Swap your quotes: `xterm -e "cockroach start --insecure --store='node$i'"`. `$i` needs to be expanded when `xterm` runs, not when `cockroach` runs. – chepner Apr 28 '18 at 15:38
oh... yeah I see, thanks alot – Robin Schmidt Apr 28 '18 at 15:40

Using variables in bash script command parameters

0 Answers0