Javascript how to split string by multiple delimiters and include them in the result

Question

I'm trying to separate string by multiple delimiters and include them in the result. Considering all consecutive non-whitespace characters as individual words. Example: "I'm working on a new super-project wow. Yay!" becomes "!Yay .wow project-super new a on working I'm" My code sofar:

function test(string){
    console.log(string.split(/([.'\!'+a-zA-Z]+)/g ).reverse().join(' ') );
}

var string ="I'm working on a new super-project wow. Yay!"
test(string)

the output so far is: Yay! wow. project - super new a on working I'm

I'm still getting the wrong result. Any help would be appreciated.

I hope this can help you. https://stackoverflow.com/questions/5993779/use-string-split-with-multiple-delimiters?utm_medium=organic&utm_source=google_rich_qa&utm_campaign=google_rich_qa — Nicolas Takashi, Apr 30 '18 at 19:48
Current accepted answer keeps `super-project` as is but it should be `project-super`. [Check this](https://stackoverflow.com/a/50107371/1020526). — revo, Apr 30 '18 at 20:25
Roman, your *Considering all consecutive non-whitespace characters as individual words* requirement clashes with the expected result. My answer is in line with that requirement. Please make sure you selected the right answer as accepted. — Wiktor Stribiżew, May 01 '18 at 19:50

score 1 · Accepted Answer · answered Apr 30 '18 at 19:55

I suggest swapping words with the glued punctuation first (using .replace(/(^|\s)(\w+)([^\w\s]+)(?!\S)/g,"$1$3$2")) and then match all non-whitespace chunks and join with a space:

function test(string){
    console.log(string.replace(/(^|\s)(\w+)([^\w\s]+)(?!\S)/g,"$1$3$2").match(/\S+/g).reverse().join(' ') );
}
//"!Yay .wow project-super new a on working I'm"
var string ="I'm working on a new super-project wow. Yay!"
test(string)

The word-punctuation swapping regex details:

(^|\s) - Group 1: start of string or whitespace
(\w+) - Group 2: one or more word chars
([^\w\s]+) - Group 3: any 1+ words other than word and whitespace chars
(?!\S) - no non-whitespace char is allowed immediately to the right of the current location. Together with (^|\s), these subpatterns form whitespace word boundaries.

score 0 · Answer 2 · answered Apr 30 '18 at 19:57

Rules are not so clear, there may be more cases to include but if not, splitting on [!?.\s-]+ (or whatever delimiters are) would be a solution. You don't need to hack into .replace() or .match() methods:

var str = "I'm working on a new super-project wow. Yay!";
console.log(str.split(/([!?.\s-])/g).reverse().join(''));

Javascript how to split string by multiple delimiters and include them in the result

2 Answers2