import numpy as np
def relu(z):
return np.maximum(0,z)
def d_relu(z):
z[z>0]=1
z[z<=0]=0
return z
x=np.array([5,1,-4,0])
y=relu(x)
z=d_relu(y)
print("y = {}".format(y))
print("z = {}".format(z))
The code above prints out:
y = [1 1 0 0]
z = [1 1 0 0]
instead of
y = [5 1 0 0]
z = [1 1 0 0]
From what I understand the function calls I've used should only be doing passing by value,passing a copy of the variable.
Why is my d_relu function affecting the y variable?
Your first mistake is in assuming python passes objects by value... it doesn't - it's pass by assignment (similar to passing by reference, if you're familiar with this concept). However, only mutable objects, as the name suggests, can be modified in-place. This includes, among other things, numpy arrays.
You shouldn't have d_relu modify z inplace, because that's what it's doing right now, through the z[...] = ... syntax. Try instead building a mask using broadcasted comparison and returning that instead.
def d_relu(z):
return (z > 0).astype(int)
This returns a fresh array instead of modifying z in-place, and your code prints
y = [5 1 0 0]
z = [1 1 0 0]
If you're building a layered architecture, you can leverage the use of a computed mask during the forward pass stage:
class relu:
def __init__(self):
self.mask = None
def forward(self, x):
self.mask = x > 0
return x * self.mask
def backward(self, x):
return self.mask
Where the derivative is simply 1 if the input during feedforward if > 0, else 0.
